Question 256670
Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y=mx+b. 
(-7,7);4x=3y+7
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Write the given equaion in slope-intercept form:
y = (4/3)x - (7/3)
slope = 4/3
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Any line parallel to this line must have slope = 4/3
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Form of the equation you want is y = mx + b
You know m=4/3 and you know y = 7 when x = -7.
So, solve for "b":
7 = (4/3)(-7) + b
(21/3) = (-28/3) + b
b = (49/3)
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Equation you want:
y = (4/3)x + (49/3)
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Cheers,
Stan H.