Question 256592
The method we will use is called the "elimination" or "multiplication-elimination" method. We want to get rid of a variable. Here was the original question:
(i) {{{6x + 15y = -45}}}
(ii) {{{6x + 5y  = -35}}}
As we look at these equations, it would be easier to eliminate the variable. So, multiply (ii) by (-1) to get
(iii) {{{-6x - 5y = 35}}}
Now add (i) and (iii) to get
(iv) {{{10y = -10}}}
solving for y, we get
{{{y = -1}}}
replace y with -1 into (i) to get
(v) {{{6x + 15*(-1) = -45}}}
solving for x, we get
{{{6x = -30}}}
{{{x = -5}}}
Our coordinate is (-5,-1)