Question 256537
We are given:
{{{x^2-6x=27}}}
step 1 - set = 0 as
{{{x^2 - 6x - 27 = 0}}}
step 2 - factor to get
{{{(x-9)(x+3) = 0}}}
step 3 - solve each part to get
x = 9 and x = -3.
Both answers are real.