Question 256521
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Let *[tex \Large x] represent the first number


Let *[tex \Large y] represent the second number


4 times the first number is then:  *[tex \Large 4x]


11 more than the second number is:  *[tex \Large y\,+\,11]


"Is" means equals, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ =\ y\ +\ 11]


which gives us the first equation.


The sum of the numbers is 14:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 14]


which can be re-stated:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 14\ -\ x]


Take this expression for *[tex \Large y] and replace *[tex \Large y] in the first equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ =\ \left(14\ -\ x\right)\ +\ 11]


Just solve for *[tex \Large x].  Once you discover the value of *[tex \Large x], you can subtract that from 14 to get the value of *[tex \Large y]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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