Question 256501
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The sum of the interior angles of any *[tex \Large n]-gon is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ S_{IA}\ =\ 180\left(n\ -\ 2\right)]


Therefore the measure of one interior angle of any regular *[tex \Large n]-gon is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ IA\ =\ \frac{180\left(n\ -\ 2\right)}{n}]


Substitute 8 for *[tex \Large n] and do the arithmetic.  Then substitute 6 for *[tex \Large n] and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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