Question 256389
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First look at the prime factorization of 270.  The quick way is to realize that you have 27 times 10 or 3 times 3 times 3 times 5 times 2.


If you are going to divide 270 by something and get a positive prime number, then that positive prime number must be one of the above prime numbers, namely 2, 3, or 5.  Furthermore, the 'something' must be the product of all of the prime factors except for the one that is the desired quotient.  In order for <i>n</i> to be odd, it cannot have 2 as a factor.  Therefore, the quotient must be 2 and <i>n</i> must be the product of 27 times 5 = 135.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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