Question 256296
Let the numbers be x, x+1 and x+2.
x(x+1)-3(x+2)=57
x^2+x-3x-6=57
x^2-2x-6=57
x^2-2x-63=0
(x-9)(x+7)=0
x=9, x=-7 Two different sets of correct answers: 9, 10, 11 and -7, -6, -5
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Ed