Question 256341
substituting x for t^(1/6)


4x^2 - 5x + 1 = 0


factoring ___ (4x - 1) (x - 1) = 0


4x - 1 = 0 ___ x = 1/4 ___ substituting ___ t^(1/6) = 1/4 ___ t = 4^(-6)


x - 1 = 0 ___ x = 1 ___ substituting ___ t^(1/6) = 1 ___ t = 1