Question 256267
Let x = integer
Let x+1 = the consecutive integer


If seven times the larger of two consecutive integers is forty three less than eight times the smaller, the equation becomes:  {{{7(x+1)=8x-43}}}


Now solve for x, then check your answer.
{{{7(x+1)=8x-43}}}
{{{7x+7=8x-43}}}
{{{7+43=8x-7x}}}
{{{50=x}}}


Check:
{{{7(x+1)=8x-43}}}
{{{7(50+1)=(8*50)-43}}}
{{{7*51=400-43}}}
{{{357=357}}}  The answer checks!


Your integers are: 50 and 51