Question 256324
find  of the inverse this equation  y=log3(x+2)-2
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Interchange x and y:
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x = log3(y+2)-2
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Solve for "y" to get the inverse:
log3(y+2) = x+2
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y+2 = 3^(x+2)
y = [3^(x+2)] - 2
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Cheers,
Stan H.