Question 256204
1. 2x^2 - 3x - 11 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(3+-sqrt[-3^2-4*2*-11])/2*2
x=(3+-sqrt[9+88])/4
x=(3+-sqrt97)/64x=(3+-9.849)/6
x=(3+9.849)/4
x=12.849/4
x=3.2122 ans.
x=(3-9.849)/4
x=-6.849/4
x=-1.7122 ans.
2. 3x^2 + 48 = 0
3(x^2-16)=0
3(x+4)(x-4)=0
x+4=0
x=-4 ans
x-4=0
x=4 ans.
3. 2x^2 - x + 1 = 0
(2x+1)(x-1)=0
2x+1=0
2x=-1
x=-1/2 ans.
x-1=0
x=1 ans.