Question 256207
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The sum of the interior angles of any <i>n</i>-gon is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 180\left(n\,-\,2\right)] degrees.


Substitute 10 for <i>n</i>, do the arithmetic, then subtract 1350, the sum of 9 of the angles, from the sum of all ten to get the measure of the last one.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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