<PRE><B>Question 256117</B>
(a) What is the probability of producing at least 232,000 barrels? 
50% of them are at least 232,000, so prob = 1/2
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(b) Between 232,000 and 239,000 barrels? 
This is from sigma = 0 to sigma = 1, so we have 34%
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(c) Less than 239,000 barrels?
this is 50% + 34% = 84% ~ .84
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(d) Less than 245,000 barrels? (e) More than 225,000 barrels?
We need to fin a z-score: (245000-232000)/7000 = 13000/7000 = 1.85. 
.4678 + .5 = .9678</PRE>