Question 32286
Hello!
This appears to be a "rationalize the denominator" problem, as there is nothing else to solve in the expression you provide. You have:

{{{2/(sqrt(3)+1)}}}

You can now use the following rule
{{{(a+b)(a-b)=a^2-b^2}}}

So, multiply your expression by {{{(sqrt(3)-1)/(sqrt(3)-1)}}} (this doesn't affect it, as it's the same as multiplying it by 1.)

{{{2/(sqrt(3)+1)*(sqrt(3)-1)/(sqrt(3)-1)}}}

But using the above rule, this expression becomes:
{{{2*(sqrt(3)-1)/(sqrt(3)^2 - 1^2)}}}
{{{2*(sqrt(3)-1)/(3 - 1)}}}
{{{2*(sqrt(3)-1)/2}}}
{{{sqrt(3)-1}}}

So your expression becomes simply {{{sqrt(3)-1}}}


I hope this helps!
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