Question 256134
Here is the original question:
(i) {{{x^2=x+12}}}
step 1 - move everything over to 1 side so it is = 0 we get
(ii) {{{x^2 - x - 12 = 0}}}
step 2 - factor the left side to get
(iii) {{{(x-4)(x+3) = 0}}}
step 3 - solve each parenthesis for x and we get
x-4 = 0
x = 4
x+3=0
x=-3