Question 256124
{{{(7+3i)/(3+9i)}}}

The first step in writing this expression in standard form is to multiply both the numerator and denominator by the complex conjugate of the denominator.  Remember that the complex conjugate of a+bi is a-bi.  So here, we want to multiply the numerator and denominator by 3-9i.

{{{((7+3i)/(3+9i))((3-9i)/(3-9i))}}}

This gives:

{{{(21-63i+9i-27i^2)/(9-27i+27i-81i^2)}}}

Now we combine like terms, remembering that i^2 = -1.

{{{(21-54i+27)/(9+81)}}}

{{{(48-54i)/(90)}}}

{{{48/90 - (54/90)i}}}

{{{8/15 - (3/5)i}}}