Question 256124
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Multiply by the conjugate of the denominator divided by itself.  If *[tex \Large \alpha\,+\,\beta i] is a complex number, then *[tex \Large \alpha\,-\,\beta i] is its conjugate.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{7\,+\,3i}{3\,+\,9i}\right) \left(\frac{3\,-\,9i}{3\,-\,9i}\right)]


The denominator is now the difference of two squares.  Remember that *[tex \Large i^2\ =\ -1].


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{48\,-\,54i}{100}\ =\ 0.48\ -\ 0.54i]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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