Question 256116


{{{(6x+4)^2=77}}} Start with the given equation.



{{{6x+4=""+-sqrt(77)}}} Take the square root of both sides.



{{{6x+4=sqrt(77)}}} or {{{6x+4=-sqrt(77)}}} Break up the "plus/minus" to form two equations.



{{{6x=-4+sqrt(77)}}} or {{{6x=-4-sqrt(77)}}} Subtract {{{4}}} from both sides.



{{{x=(-4+sqrt(77))/6}}} or {{{x=(-4-sqrt(77))/6}}} Divide both sides by 6 to isolate x.



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Answer:



So the solutions are {{{x=(-4+sqrt(77))/6}}} or {{{x=(-4-sqrt(77))/6}}}.