Question 256043
The question was
(i) {{{-10x^2 + 30x - 20 = 0}}}
divide by -10 to get
(ii) {{{x^2 - 3x + 2 = 0}}}
factoring, we get
(iii) {{{(x-2)(x-1)=0}}}
solving each for x, we get
x = 2
x = 1