Question 255798
 One of the problems is: y=3x-10 and the other equation that goes with it is y=2x-5
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Given that y = 3x-10, that means that any place you see "y", you can substitute (3x-10)
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The 2nd equation:
y = 2x - 5
From the 1st equation, substitute (3x - 10) for y
3x - 10 = 2x - 5
3x - 2x = -5 + 10
x = +5
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Now substitute 5 for x in the 1st equation to find y
y = 2x - 5
y = 2(5) - 5
y = 10 - 5
y = 5
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Check the solutions by sustituting for x and y in the 2nd equation
 y = 2x - 5
 5 = 2(5) - 5
5 = 10 - 5
5 = 5; true; confirms our solutions of x = 5 and y = 5
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Did this shed some light on substitution??