Question 255744
The sum of the squares of two positive consecutive integers is 41. Find integers. Show steps please^^

integer I
next consecutive integer I+1

I^2+(I+1)^2=41

I^2+((I+1)(I+1))=41
I^2+I^2+2I+1=41
2I^2+2I+1=41
2I^2+2I-40=0
I^2+I-20=0
(I+5)(I-4)=0
I=-5 and I=4
-5 is not positive
so I is 4

I+1=5

integers are 4 and 5