Question 255681
What is the volume of a tent with measurements:
h=2m
b=3m
l=?
SA (outside of tent)=38m^2 
Please explain. Thank you in advance!

thinking this is a triangular tent

2 sides for the top, 1 side for bottom, 1 front, 1 back 
that is 5 sides
front=back=(1/2)(3)(2)=(1/2)(6)=3 --> total SA 6m^2

((1/2)b)^2+h^2=(width of one of the top sides)^2 let's call it slope^2
((1/2)(3))^2+2^2
1.5^2+4
2.25+4
6.25=slope^2
2.5=slope

top=2*2.5*l=5*l
bottom=3*l

5*l+3*l+6=38
8*l=32
l=4

V=hbl
v=2*3*4=6*4=24 m^3

oh drat, I realized I made an error

volume of the prism standing up right would be area of base times the height
in this case area of one of the triangular sides times the length

V should be 1/2 * base * height * length
V= 1/2 * 3 * 2 * 4
V= 1/2 * 6 * 4
V= 1/2 * 24
V=12 m^3 NOT 24 m^3 

sorry