Question 255674
{{{-8q^2+2q+1=0}}}

a=-8
b=2
c=1

So, {{{b^2-4ac}}} is:

{{{2^2-4(-8)(1) = 4+32 = 36

Now, since {{{b^2-4ac > 0}}} we know that the formula has 2 real solutions.