Question 32176
xy2(squared)+xyz-z2(square)

put the respective values of x ,y and z in the equation,,,, and we get

= (36*1/6)^2 + (36*1/6*9) - (9)^2....here ^ denotes power sign

on solving brackets we get,,,,,,,

= (6)^2 + 54 - 81

= 36 + 54 - 81

= 90 - 81 

= 9 ...........

Hope this will help you 

Please feel free to revert back for any further queries.