Question 255665
0.9=log(0.2-x/x)

not sure if this is 0.9=log10 (0.2 - (x/x))
or                  0.9=log10 ((0.2-x)/x)

0.9=log10 (0.2-(x/x))
0.9=log10 (0.2-1)
0.9=log10 (-0.8)
can not take log10 of a negative number

0.9=log10 ((0.2-x)/x)
0.9=log10 (y)

y = b^x <==> logb(y) = x
10^0.9=y

10^0.9=(0.2-x)/x
(10^0.9)x=0.2-x
(10^0.9)x+x=0.2
((10^0.9)+1)x=0.2
(7.943282+1)x=0.2
(8.943282)x=0.2
x=0.022363