Question 255655
{{{log(x+2)=log x+2}}}
rewriting the 2 as 2log(10) we get
{{{log(x+2)= log(x) + 2log(10)}}}
then by power rule, we get
{{{log(x+2)= log(x) + log(10)^2}}}
Using rules of logs, we get
{{{log(x+2) = log(100x)}}}
next getting rid of the logs, we
{{{(x+2) = 100x}}}
solving for x, we get
{{{x = 2/99}}}