Question 255631
Here is the equation:
{{{x^2-4x=8}}}
PART A -
step 1 = rewrite the equation as
{{{x^2 - 4x + ___ = 8 + ____}}}
The blanks are waiting for numbers.
step 2 - take 1/2 of middle term and square it to get (-2)^2 = 4. Put that number in the first blank as:
{{{x^2 - 4x + (-2)^2 = 8 + _____}}}
step 3 - place 4 in the blank of the other side as
{{{x^2 - 4x + (-2)^2 = 8 + 4}}}
step 4 - rewrite the left side as a quantity squared and simplify the right side to get
{{{(x-2)^2 = 12}}}
PART B - 
take square root of both sides to get
{{{(x-2) = sqrt(12)}}}
add 2 to both sides
{{{x = 2 + or - sqrt(12)}}}
{{{x = 2 + or - 2sqrt(3)}}}