Question 255576
Let the cars meet at a time t  after 12 noon.
The speed of car A = 50 mph
The distance travelled by A in(t+1)hours is x = 50(t+1)miles
The speed of car B = 75 mph
The distance travelled by B in t hours is y = 75t miles
But, x+y = 400 miles
    50(t+1)+75t = 400
    50t+50+75t = 400
    125t = 400-50
    125t = 350
       t = 350/125
       t = 2 100/125 hours
       t = 2h 48 minutes
The distance travelled by B = 75t = 210 miles
But Fresno is 150 miles from LA
So the distance between the point of meeting and Fresno = 210-150 = 60 miles