Question 255501
Let the width of the rectangle be x.
Then its length = 2x-2
Then perimeter is 2(x+2x-2) = 32
                    (3x-2) = 32/2
                     3x = 16+2
                     3x = 18
                      x = 18/3
                      x = 6 cms
Therefore area of the rectangle= x(2x-2)
                               =2x^2-2x
                               = 2(6)^2-2*6
                               = 2*36-12
                               = 72-12
                               =60 sq.cms