Question 255522
Identify the vertex and the y-intercept of the graph 
of the function y = -3(x + 2)^2 + 5
----------------
The function is in the vertex form y = a(x-h)^2+k
where the vertex is (h,k).
---
Your problem: vertex is (-2,5)
When x = zero, y = -3*2*2+5 = -7
so the y-intercept is (0,-7.
----
Since a = -3 is negative the parabola opens downward.
------------------------------------------------
{{{graph(400,300,-10,10,-20,10,-3x^2-12x-7)}}}
======================================================
Cheers,
stan H.