Question 255494
1) The slope of a line that is parallel to the line y=4/3x+13 is m = 4/3
   The given line is of the form y=mx+c
2. Let the equation of a line that is parallel to the line y=4x+32 be
                      y=4x+c   ...(1)  where c is a constant.
Given, the point (6,-2) lies on it.
Put x=6 and y=-2 in (1)
We get,     -2 = 4*6+c
            -2-24 = c
                c = -26
Substituting in (1), we get
the wquation of the required line is y=4x-26