Question 255458
Find 2 consecutive 2 digit numbers whose product is 812.
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1st: x
2nd: x+1
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Equation:
x(x+1) = 812
x^2 + x - 812 = 0
(x-28)(x+29) = 0
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If x = 28, x+1 = 29
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If x = -29, x+1 = -28
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Cheers,
Stan H.