<PRE><B>Question 32212</B>
y=0.005x^2-2x+200
a)32=0.005x^2-2x+200
   0=0.005x^2-2x+168
Graphing this I find x=120, giving the point (120,32)
b)18=0.005x^2 etc.
  0 =0.005x^2-2x+182
Graphing this I find x=140, giving the point (140,18)
c) d=sqrt[(32-18)^2 + (120-140)^2]= 24.4 ft
d) The average is the distance divided by the time change:
 ave.= 24.4 ft/ (0.23) sec. = 106.09 ft./sec.
Cheers,
stan H.
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