<PRE><B>Question 255434</B>
How much water should be added to 32 ounces of a 30% solution of alcohol to dilute it to a 16% solution?
Formula to develop the problem 
:
Let x = amt of water
:
.30(32) = .16(32+x)
9.6 = 5.12 + .16x
9.6 - 5.12 = .16x
4.48 = .16x
x = {{{4.48/.16}}}
x = 28 oz of water</PRE>