Question 255419
{{{ 3*sqrt(32x^9y^4)}}}
we simplify what is in the radical as
{{{3*sqrt(2*2*2*2*2*x*x*x*x*x*x*x*x*x*y*y*y*y)}}}
we need to find pairs of somsething in order to take one of them out.
We can take out 2 2's, 4 x's, and 2y's to get
{{{3*2*2*x*x*x*x*y*y*sqrt(2x)}}}
simplified, we get
{{{12x^4y^2*sqrt(2x)}}}
not sure if the negative was in these.