Question 255261
{{{(x+2)^2*(x-2)^2}}}
this is the same as
{{{((x+2)(x-2))^2}}}
now (x+2)(x-2) = x^2-4, so we get
{{{(x^2-4)^2}}}
squaring this gets us
{{{x^4 - 8x^2 +16}}}