Question 255219
Let the length of the rectangle = x
and the width of the rectangle  = y
Given, perimeter 2(x+y) = 54 mts
                   x+y  = 54/2
                    x+y = 27 
                      y = 27-x  ...(1)
Also, area xy = 180
           x(27-x) = 180
           27x-x^2 = 180
          -x^2+27x-180 = 0
           x^2-27x+180 = 0
           (x-15)(x-12)= 0
                     x = 15  and x = 12
Therefore, the length of the rectangle = 15 mts
and the width of the rectangle  is y = 27-15 = 12 mts