Question 254981
The given equation of the line is
           y = (8/7)x-9
Slope of this line = 8/7
The slope of a line perpendicular to this line = -7/8
Ifthe perpendicular line passes through the point (8,-1) then its equation is
             [y-(-1)] = (-7/8)(x-8)
              8(y+1)  = -7(x-8)
                8y+8  = -7x+56
             7x+8y+8-56 = 0
             7x+8y-48 = 0