Question 254908
*[invoke length_of_equilateral_triangle_inscribed_in_the_circle 6]
.
A(equilateral triangle)=s^2sqrt(3)/4
(10.39^2*sqrt(3))/4
=46.74 sq in
.
A(circle)=pi*r^2
=pi*6^2
=113.1 sq in
.
113.1-46.74=66.35 area of all 3 segments cut off by a side of the triangle.
66.35/3
=22.12 sq in, area of the segment cut off by one side of the triangle.
.
Ed