Question 31911
Y=(X^2-2(X)(2)+2^2)-2^2-5=(X-2)^2-9
SO LINE OF SYMMETRY IS X-2=0...OR....X=2 
YOU CAN PLOT AXIS X=2 AND VERTEX (2,-9) FIRST..THEN INTERCEPTS(0,-5)AND (5,0)AND (-1,0)..TO PLOT THE GRAPH 
 {{{ graph( 600, 600, -8, 10, -15, 100, (x-2)^2-9) }}}