Question 254777
Let a and b be the two sides of a rectangle
Then perimeter 2(a+b) = 56
                 (a+b) =28  ..(1)
Area             ab = 96    ...(2)
Next, (a-b)^2 = (a+b)^2-4ab
              =(28)^2-4*(96)
              = 784-384
      (a-b)^2 = 400
          a-b = 20   ...(3)
(1)+(3)=>  2a = 28+20
           2a = 48
            a = 24
Substituting in (1),
          24+b = 28
             b = 28-24
             b = 4
Therefore the sides are 24 and 4