Question 254665
Here is the problem:
{{{x^3 - 2x^2 -15x = 0 }}}
step 1 - lok for any GCF. We have x, so we can rewrite as
{{{x(x^2 - 2x - 15) = 0}}}
step 2 -factor if possible. we get
{{{(x)(x-5)(x+3) = 0}}}
step 3 - set each (_) = 0 and solve to get
x = 0
x = 5
x = -3