Question 254601
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Your method, given correct arithmetic, should work just fine.  However, I think that you are doing too much work.


If *[tex \Large \frac{1}{12}] is the amount for 1 person, then *[tex \Large \frac{10}{12}\ =\ \frac{5}{6}] would be the amount for 10 people, n'est-ce pas?


*[tex \Large 2\frac{1}{4}\ = \frac{8}{4}+\frac{1}{4}\ =\ \frac{9}{4}]


Let's multiply:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{9}{4}\right)\left(\frac{5}{6}\right)\ =\ \left(\frac{3}{4}\right)\left(\frac{5}{2}\right)\ =\ \frac{15}{8}\ =\ 1\frac{7}{8}]


That's the math class answer.  If you are really cooking something, just round it to 2 cups.  Better yet, make the entire 12 person recipe -- out of 10 people <b><i>someone</i></b> will want seconds.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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