Question 254589
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Turn it into a fraction where the remainder is the numerator and the divisor is the denominator.  Then reduce to lowest terms.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 50\,\div\,15\ =\ 3\ +\ \frac{5}{15}\ =\ 3\frac{1}{3}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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