Question 254433
The given equation is
             log(4-x)=log(x+8)+log(2x+13)
             log(4-x) = log(x+8)(2x+13)
Taking anti-log,
                (4-x) = (x+8)(2x+13)
                 4-x  = 2x^2+13x+16x+104
                    0 = 2x^2+29x+104+x-4
                    0 = 2x^2+30x+100
Dividing by 2,we get
        x^2+15x+50 = 0
        (x+5)(x+10) = 0
                 x = -5 or -10