Question 254421
The given equatins are,
                        x-1=y+1   ...(1)
                        x+1=2(y-1)...(2)
(1)-(2)=>             -1-1 = y+1-[2y-2]
                         -2= y+1-2y+2
                         -2 = -y+3
                          y = 3+2
                          y = 5
Substituting in (1),   x-1 = 5+1
                       x-1 = 6
                         x = 6+1
                         x = 7
Therefore the solution is (7,5)