Question 254432
Let x and y be the speeds ofthe planes.
In 5 hours,
The distance flown by the faster plane = 5x
The distance flown by the slower plane = 5y
Given, the distance between the planes
                      5x-5y = 300   ...(1)
Also, total distance flown by the planes
                      5x+5y = 5300  ...(2)
(1)+(2)=>             10x = 5600
                        x = 5600/10
                        x = 560   kmph
Substituting in (1), 5*560-5y = 300
                          -5y = 300-2800
                          -5y = -2500
                            y = (-2500)/(-5)
                            y = 500 kmph
The distance flown by the faster plane = 5*560 = 2800km
The distance flown by the slower plane = 5*500 = 2500km