Question 254383
 Let the two numbers be x and y.
Given,     x+y = 50  ..(1)
Also,      x/y = 9/16
            16x= 9y
        16x-9y = 0  ...(2)
(1)*9=> 9x+9y = 450 ...(3)
(2)+(3)=> 25x = 450
            x = 450/25
            x = 18
Substituting in (1), we get
          18+y = 50
             y = 50-18
             y = 32
Therefore the required numbers are 18 and 32