Question 254215
A. y=-2(x+1)^2+8 
- Find the coordinates of the vertex
vertex: (-1,8)
- Direction of opening
opens down because of (-) in front of 2.
- Identify if the graph is wider or narrower than normal
Skinny because 2 > 1
- Find the equation of the axis of symmetry
Axis of symmetry is x = -1
- Find the y-intercept
(0,6)
- Find the x-intercept
(-1,0)(-3,0)
- Give the domain and range for each quadratic
domain: all reals
range: Y<= 8
 Draw a sketch of the quadratic
{{{ graph( 300, 200, -5, 15, -10, 10, -2(x+1)^2+8) }}}

B. y=x^2+6x-16 
FIrst we complete the square to get vertex form as:
y = (X+3)^2-25
- Find the coordinates of the vertex
vertex: (-3,-25)
- Direction of opening
opens up
- Identify if the graph is wider or narrower than normal
normal opening
- Find the equation of the axis of symmetry
axis of symmetry is x = -3
- Find the y-intercept
(0,-16)
- Find the x-intercept
(2,0) (-8,0)
- Give the domain and range for each quadratic
domain: all reals
range: y >= -25
- Draw a sketch of the quadratic
{{{ graph( 300, 200, -10, 10, -40, 0, (x+3)^2-25) }}}