Question 254122
If xy = 3, xz = 4, and yz = 6, Find the value of x^2 + y^2 + z^2
<pre><font size = 4 color = "indigo"><b>
{{{yz=6}}}, so {{{z=6/y}}}, plug that in

{{{xz=4}}} and get {{{x(6/y)=4}}} or {{{6x/y=4}}} or {{{6x=4y}}} or {{{y=6x/4=3x/2}}}

Plug that in {{{xy=3}}}

{{{x(3x/2)=3}}}, or {{{3x^2/2=3}}} or {{{3x^2=6}}} or {{{x^2=2}}}

--------------------------------------------------------------

{{{xy=3}}}, so {{{x^2y^2=9}}} so {{{y^2=9/x^2=9/2}}}

{{{xz=4}}}, so {{{x^2z^2=16}}} so {{{z^2=16/x^2=16/2=8}}}

--------------------------------------------------------------

{{{x^2+y^2+z^2=2+9/2+8=4/2+9/2+16/2=29/2}}}

Edwin</pre>